Digital SAT November 2026 11I — Evidence, Conditional Probability, and Shifted Quadratics

Last updated: November 2026 · By the AllSatPapers Content Team

November 2026 DSAT 11I is particularly useful for learning to track what a question actually conditions on. The Reading and Writing section asks whether a conclusion follows from a hierarchy of materials, whether two economic hypotheses receive different kinds of support, and how a punctuation choice changes the structure of an explanation. Math turns the same habit into calculations: identify the population left after a condition, the quantity that decays, and the function represented by a table.

The supplied file contains two Reading and Writing modules and two Math modules, followed by their respective keys and explanations. It is a 98-question set rather than a question bank. Its value after October practice comes from recognizable families with changed targets. A familiar steel passage can ask about chromium rather than manganese; a familiar table can hide a different vertical shift. This review works through six cases and compares eight specific earlier questions so that recognition leads to a fresh solution.

Practice alongside the analysis: Explore the 2026 Digital SAT papers and answer-key collection.

What the supplied 11I file contains

Dates and form labels identify the supplied archive file; they do not independently establish administration provenance or a region. Easy, Medium, and Hard are labels printed on individual questions, not a verified adaptive route or a measured difficulty ranking. The 98-question total counts printed occurrences, including related variants. Page references throughout this article are one-based PDF positions, which may differ from printed footer numbers. The selected pages were rendered and inspected; the worked answers below were reasoned independently and checked against the included tables.

Reading and Writing Module 1: separate categories before drawing conclusions

The opening vocabulary questions on pp.1–4 reward evidence from the immediate context rather than a dictionary definition in isolation. The later reading sequence changes the scale of the task. Quotation evidence on p.10 requires a line that proves the proposed interpretation; the moth study on p.11 requires a finding that supports a proposed function; the steel hierarchy on p.14 requires a relationship already contained in the passage. These are three different standards of support. A quotation can directly depict a behavior, an experiment can make a hypothesis more plausible, and a category statement can entail a conclusion. Do not demand the same kind of proof from all three.

Page 11 illustrates the distinction. Sounds begin with simulated attacks and stop shortly afterward, connecting the response to a threat. That is the strongest offered support for the predator-directed account, but it is not the same evidence as an actual predator abandoning an attack. In review, write the claim and the specific bridge separately. This makes it easier to reject choices that merely repeat a study detail, such as each species usually making one sound.

The grammar sequence beginning on p.16 should be approached structurally. The sand question on p.17 needs a boundary between independent statements; remembering a colon from an earlier Pfeiffer Beach version would give the wrong method. At the notes-based end of the module, mark the requested audience or comparison before selecting facts. These shifts explain why this module can feel uneven: the amount of text is not a reliable measure of the number of relationships you must hold in mind.

Reading and Writing Module 2: coordinate chronology, hypotheses, and clause structure

Module 2 concentrates several tasks in which two pieces of information must remain distinct. The Grande Terre question on p.38 compares a 90-million-year separation with much younger clade crown ages. The Rajavi table on p.42 distinguishes a contraction hypothesis about product-line length from an expansion hypothesis about advertising. The carbon-dioxide modeling question on p.44 compares grid resolution while holding the seasonal setting fixed. In all three, a plausible subject-related sentence can fail because it compares the wrong pair.

For the cross-text item, place the dates on one line before reading ambitious conclusions. A clade originating 60 million years ago cannot predate a separation 90 million years ago; the 5.1-million-year example is younger still. The question, however, asks about the older Gondwanan species and their relationship to current clades, so the conclusion must respect that broader scope. For the modeling item, more data from a finer grid is not enough: the finding must show a change in the modeled phenomenon.

The final third adds a different kind of bookkeeping. The centaur sentence on p.49 embeds a contrast inside an explanation, and the opera transition on p.54 moves from a historical cause to a present consequence. Page 58 asks for the order of two topics in a book, whereas p.59 asks for a comparison of park benefits. A student who skims familiar names but overlooks the requested relationship will lose points across several superficially unrelated skills.

Math: model the relevant quantity, then check its boundary behavior

Math Module 1 combines direct calculations with questions that require the right representation. The trigonometric expression on p.68 asks for cos(9π/2): remove full 2π turns and evaluate cos(π/2), obtaining zero. The perpendicular-line question on p.87 is a useful endpoint because it tests a symbolic relationship rather than a numerical slope. A line perpendicular to slope m has slope −1/m, so moving one unit right from (6,2) gives (7,2−1/m). The condition m>1 is compatible with that negative, smaller-magnitude change; it does not turn the perpendicular slope into −m.

Module 2 makes context restrictions more consequential. On p.100, fifteen packages weigh 240 pounds in total, five account for 90, and each weighs at least four. The remaining ten total 150, so one of those packages can weigh at most 150−9(4)=114 pounds. This is an extremum argument: make the other nine as small as allowed. On p.104, a bamboo model changes rates after four hours; the later expression must preserve the height already accumulated at the change point. Both questions reward checking the boundary case before trusting an equation.

The three Math studies below use complementary quantities, conditional populations, and transformed functions. A calculator can evaluate any proposed expression, but it cannot choose which population or function the words designate. Set up that interpretation first. Then use a small check—day zero, the conditional column total, or a known table entry—to catch a model that looks algebraically polished but represents the wrong object.

Six worked questions: reasoning, distractors, and useful checks

Reading and Writing M1 Q14 — A hierarchy is not a list

Source: PDF p.14; included answer table p.28. Answer: D.

The passage divides stainless steel into ferritic and austenitic categories. Cooking utensils use the ferritic category, which has a higher chromium proportion. Dishwashers use the 200 series, a subtype of austenitic steel. Therefore the dishwasher steel has less chromium than the utensil steel: D. The conclusion follows from category membership, even though the passage also supplies nickel, iron, magnetism, and crystal-structure information.

A compact diagram is more useful than rereading every sentence: ferritic → utensils; austenitic → 200 series/dishwashers and 300 series/pharmaceutical afterburners. Attach each property to the correct branch. Face-centered cubic structure belongs to austenitic steel, not the utensil branch. The relative nickel distinction separates the two austenitic subtypes; it does not erase the larger ferritic-versus-austenitic distinction.

The distractors exploit movement between branches. Similar uses do not establish similar magnetism. A characteristic of austenitic steel cannot be assigned to ferritic utensils merely because both are stainless steel. Nor does a stated chromium threshold justify an unrelated absolute threshold for a particular subtype: “lower than” a category with at least 11% does not by itself establish “below 10.5%.” This is why D's comparative claim is stronger than a more specific-looking numerical assertion.

For timing, stop building the diagram as soon as the requested comparison is settled. This is a deduction from the supplied passage, not a metallurgy knowledge test. Replacing the real objects with F, A200, and A300 can make the logic clearer and prevents an earlier steel question from supplying an answer that this version never asks for.

Source image: 2026 11I.pdf, PDF p.14.

Reading and Writing M2 Q10 — Support one hypothesis while rejecting another

Source: PDF p.42; included answer table p.60. Answer: B.

Rajavi's first hypothesis predicts a negative association between product-line length and brand equity during economic contractions. The second predicts a positive association between advertising expenditure and brand equity during expansions. The question asks for a finding consistent with support for the first but not the second. Those two conditions must be checked separately before accepting an option.

In the table, sweeteners and bath products have shorter product lines, 6.0 and 9.9, than soft drinks and cereals, 16.3 and 24.1. A contraction finding in which the shorter-line groups have higher brand equity fits the negative association. B supplies that direction. Its expansion finding of no significant brand-equity difference does not support the proposed positive advertising relationship, so it also satisfies the second requirement.

A is tempting if “higher” sounds generally favorable, but it favors the longer-line groups during contractions and reverses the first prediction. C removes the expected contraction difference while supporting the advertising prediction—the reverse of the requested combination. D includes an expansion pattern that could undermine the second hypothesis, yet its contraction comparison still fails the first. Getting one half right does not rescue a two-part answer.

The table itself lists advertising and line-length measures; it does not already report all the hypothetical performance outcomes in the choices. Treat the options as possible additional findings. A two-row scratch note—contraction: shorter line → higher equity; expansion: advertising prediction unsupported—takes less time than repeatedly comparing four long answers and protects against confusing the study's two explanatory variables.

Source image: 2026 11I.pdf, PDF p.42.

Reading and Writing M2 Q17 — A colon can introduce a complete contrast

Source: PDF p.49; included answer table p.60. Answer: C.

The sentence first establishes that two centaurs exhibit striking differences in behavior. It then explains the difference: while one object is active, the other is dormant. C, “behavior: while the,” creates that structure. The material before the colon is a complete clause, and what follows develops the promised contrast with a dependent while clause followed by its main clause.

The introductory Although clause does not make the whole opening incomplete. Its dependent material is followed by “they exhibit,” which supplies the main subject and verb. Bracket the initial concession, locate that main clause, and only then decide whether the blank can take a colon. Many students reject a valid colon because they notice a subordinating conjunction at the beginning without checking where its clause ends.

A comma before “while” does not solve the full sentence as written: it leaves the initial independent clause and the final independent dormant-object statement joined only by commas, with the while clause between them. The period or semicolon alternatives without “while” create a different problem later: the active-object statement and dormant-object statement are then independent clauses linked only by the supplied comma. A strong boundary answer must work on both sides of the blank and through the remainder of the sentence.

Read the completed structure once as “Although X, they differ: while A is active, B is dormant.” That short skeleton makes the colon's explanatory function visible. This is more dependable than the shortcut “long pause means semicolon,” and it transfers to passages where the subject matter changes but a concession introduces an explanation.

Source image: 2026 11I.pdf, PDF p.49.

Math M2 Q4 — Decay applies to the unreserved rooms

Source: PDF p.95; included answer table p.114. Answer: A.

The hotel has 200 rooms and 80 are reserved initially, leaving 120 unreserved. Every two days, the number of unreserved rooms falls by 20%. The remaining factor for that quantity is therefore 0.8 per two-day interval. After d days, the unreserved count is 120(0.8)^(d/2), and the reserved count is its complement: r(d)=200−120(0.8)^(d/2), choice A.

Three checks establish that the expression matches the story. At d=0 it returns 200−120=80, the initial reserved count. At d=2, 24 of the original 120 unreserved rooms have been reserved, so the expression returns 104. As the number of intervals grows, the unreserved term approaches zero and the reserved total approaches 200. The model cannot keep growing without bound because the hotel has a fixed capacity.

Using 0.2 as the multiplier would mean only 20% remain, an 80% decrease rather than a 20% decrease. Starting an exponential decay with 80 would model reserved rooms shrinking, contradicting the stated process. Leaving out the subtraction from 200 gives an otherwise sensible formula for the wrong quantity. These errors are easier to identify through the day-zero and direction checks than through symbolic expansion.

The exponent is a count of two-day periods, not a decoration on the percentage. If evaluating at four days, use two factors of 0.8. A graph can confirm the increasing, flattening reserved-room curve, but the complement relationship should be established before graphing. The question's continuous expression is the supplied model; it does not require inventing a separate rounding or booking rule.

Source image: 2026 11I.pdf, PDF p.95.

Math M2 Q17 — The condition selects the denominator

Source: PDF p.108; included answer table p.114. Answer: C: 15/45 = 1/3.

The object is selected from those traveling at most 30 meters per second. That condition keeps the first two speed columns and excludes the greater-than-30 column. The allowed population is therefore 20+25=45 objects. Direction B contributes 6+9=15 of those objects, so the requested conditional probability is 15/45, or one third, choice C.

Start by shading or mentally boxing the permitted columns. Only after defining that population should you count favorable outcomes. This order prevents a common mistake: seeing a direction-B row total of 23 and dividing by it automatically. The fraction 15/23 answers the reversed question, the probability of at-most-30 speed given direction B. Conditional statements are not interchangeable merely because their numerators happen to agree.

The grand total 64 is also the wrong denominator. A fraction of 15/64 would be the joint probability of direction B and the speed condition among all objects; it ignores the information already given about the selected object. The 8/64 alternative uses the direction-B cell in the excluded speed category and also ignores the condition. Each distractor has a recognizable interpretation, which makes this a particularly useful error-log problem.

Check that every favorable object belongs to the allowed group and that the probability stays between zero and one. No advanced formula is necessary, although P(B | S)=P(B∩S)/P(S) produces the same cancellation. In a timed setting, “given” or its equivalent should trigger a denominator decision before any arithmetic. Rehearse explaining the incorrect fractions in words, rather than merely recording C.

Source image: 2026 11I.pdf, PDF p.108.

Math M2 Q22 — A table of f(x)+6 is not a table of f(x)

Source: PDF p.113; included answer table p.114. Answer: −294.

The table gives y=0 at x=8 and x=12 and y=12 at x=10, where y=f(x)+6. The equal endpoint values put the symmetry axis at x=10. For the displayed y-values, write y=a(x−10)²+12. Substituting x=8 gives 0=4a+12, so a=−3. Undo the vertical shift to obtain f(x)=−3(x−10)²+6, and therefore f(0)=−300+6=−294.

There is an equally efficient factored approach. The displayed function has zeros at 8 and 12, so y=a(x−8)(x−12). Its middle value gives 12=−4a and again a=−3. At x=0 this displayed function equals −288; subtract the extra six to recover f(0)=−294. The two methods agree, and their difference makes the shift easy to audit.

The most dangerous wrong answer is −288 because it is a correctly computed intercept for the wrong graph. Another mistake is treating the table's midpoint value 12 as the vertex height of f rather than of f+6. Subtracting six from all three y-values at the outset also works: the values of f become −6,6,−6. Choose one bookkeeping convention and preserve it throughout.

Symmetry is faster here than solving a three-equation system for ax²+bx+c. The table is deliberately arranged to reveal the vertex or roots. Use that structure first, then check a supplied point. The earlier August version discussed below changes the axis, curvature, and shift; remembering its numerical intercept would erase precisely the distinctions this question tests.

Source image: 2026 11I.pdf, PDF p.113.

Earlier questions: what repeats and what changes

The table below identifies eight earlier questions across seven distinct forms. “Retuned” means that the reasoning pattern survives changes in names, figures, or choices. “Different task” means the familiar material now supports a different requested conclusion. These are page-level comparisons, not a claim that a percentage of an administration repeated. All locators are one-based PDF pages; printed footer numbers in the November file can differ.

The steel and moth pairs show two kinds of change that deserve separate practice. For steel, redraw the same hierarchy and highlight a different property; the operation is still deduction within categories. For moths, reassess the quality of the new finding itself. October's predators stopping attacks and November's attack-linked sound timing are not interchangeable observations, even though both can support the same proposed function. A productive second attempt explains why the new evidence matters rather than simply saying the passage has appeared before.

The sand and opera pairs form a useful grammar contrast. Opera preserves the logical bridge: historical use of Italian explains present encounters with Italian directions, so “Consequently” and “Hence” do the same work. Sand preserves the topic but changes the clause arrangement. A colon that introduced an explanatory though construction in the bank version cannot be imported into a new pair of statements merely because the beach is familiar. Match syntax before punctuation and relationship before transition wording.

The older chronology and quadratic comparisons reveal why a repeat list should extend beyond October. For Grande Terre, rebuild the time ordering and answer the actual scope of the question; the older text's claim about two named clades is narrower than November's question about Gondwanan species. For the quadratic, the August table gives a=−4, axis18, and f(0)=−1287, whereas November gives a=−3, axis10, and −294. The reusable achievement is choosing a representation and undoing a shift. Neither the old answer nor an apparent visual resemblance proves a new solution.

A focused study plan for 11I

Begin with the complete Reading and Writing Module 1, keeping the key pages closed. In review, label each error as a missing premise, wrong comparison, or grammar-structure mistake. Rework p.14 with a category diagram and p.11 with a one-sentence claim/evidence bridge; these two records expose different reasoning weaknesses that a general “reading error” label would conceal.

Next, isolate pp.38,42,44,49,54,58 from Module 2. Before selecting an option, state the relation being tested: older versus younger, negative versus positive association, fine versus coarse resolution, explanation, consequence, or sequence. Then complete Math and reserve the final review for the three worked models. Check d=0 for the hotel, identify the 45-object conditional population, and verify a table point after reconstructing f.

Use five concrete habits on a second pass: draw the steel tree; write both Rajavi predictions; reduce the centaur sentence to clauses; name the exponentially changing quantity; and write the conditional denominator before the numerator. Finish by solving the earlier comparison questions in a mixed order. When you can explain both the shared method and the changed target without relying on an answer letter, the repeated family has become transferable practice.

November 2026 analyses: 11A · 11B · 11C · 11D · 11E · 11F · 11G · 11H · 11I · 11J · 11K

More November analysis

Continue with Reading Module 2 evidence and inference · November vocabulary in context. For the full file map, open the November 11A–11K overview.

Every Digital SAT Paper in Our Archive

Our archived files are grouped below by their supplied labels; regional labels and dates describe the archive, rather than independent authentication of an administration.

2023

• March 2023 (3A) · May 2023 (5A) · June 2023 (6A, Easy & Hard) · October 2023 (10A) · November 2023 (11A) · December 2023 (12A–12D)

2024

• March 2024 (3A–3D) · May 2024 (5A–5D) · June 2024 (6A–6E) · August 2024 (8A–8I) · October 2024 (10A–10G) · November 2024 (11A–11F) · December 2024 (12A–12H)

2025

• March 2025 (3A–3H) · May 2025 (5A–5F) · June 2025 (6A–6E) · August 2025 (8A–8F + 8G Question Bank) · September 2025 (9A–9I + 9J Question Bank) · October 2025 (10A–10H, 10I/10J School Day, 10K Question Bank) · November 2025 (11A–11G) · December 2025 (12A Math only, 12B English only, 12C, 12D, 12E, 12F Question Bank)

2026

• March 2026 (3A Question Bank, 3B, 3C US, 3D US English only) · May 2026 (5A, 5B, 5C–5H English only) · June 2026 (6A–6D, 6E Math only, 6F/6G English only, 6H Question Bank, 6I–6K) · August 2026 (8A–8D International, 8E collection labeled “4Sets”, 8F/8G US, 8H International Question Bank) · September 2026 (9A–9C International, 9D–9H US, 9I International Question Bank) · October 2026 (10A–10D International, 10E International English only, 10F–10I US, 10J International Question Bank, 10K US Question Bank; School Day files labeled October 8, October 13 sets 1/2, October 14, October 17 sets 1/2). November 2026 (11A–11K).

Build your next practice sequence: Browse the 2026 Digital SAT collection and use the earlier page comparisons to test whether your reasoning transfers.

Keywords: November 2026 Digital SAT, DSAT 11I, SAT Reading and Writing analysis, SAT Math worked answers, October SAT repeats, allsatpapers.com.

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